Here is another parabola problem that has a square labeled PQRS with an area of 64. The top corners intersect a parabola that sits on the bottom side.
The function of the parabola is y=ax^2
The key to solving this problelm is remember that parabolas are symmetrical. Since the square root of 64 = 8, then all sides have a length of 8. QR = 8, and so the point R is (4,8)
Substitute these two points into the equation and solve
8 = a*(4)^2
8 = a* 16
8/16 = a * 16/16 a = 1/2
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